Question

if ∠egf ≅ ∠egh and ef = 70, what is eh? eh = □

Explanation:

Step1: Recall angle - bisector property

If a ray $EG$ is the angle - bisector of $\angle FGH$ ($\angle EGF\cong\angle EGH$) and $EF\perp FG$, $EH\perp GH$, then the distance from a point on the angle - bisector to the two sides of the angle are equal.

Step2: Apply the property

Since $\angle EGF\cong\angle EGH$, $EF\perp FG$, $EH\perp GH$, we have $EH = EF$.

Answer:

70