Question

ector quantities.
a plane stops from 300 mph in 15 seconds.
calculate the planes acceleration.
variables:
formula:
solve:

Explanation:

Step1: Identify variables

Initial velocity \( v_i = 300 \, \text{mph} \), final velocity \( v_f = 0 \, \text{mph} \) (stops), time \( t = 15 \, \text{s} \). Convert units: \( 300 \, \text{mph} = 300 \times \frac{1609.34}{3600} \approx 134.02 \, \text{m/s} \), \( t = 15 \, \text{s} \).

Step2: Use acceleration formula

Acceleration formula: \( a = \frac{v_f - v_i}{t} \). Substitute values: \( a = \frac{0 - 134.02}{15} \approx -8.93 \, \text{m/s}^2 \). (Negative for deceleration)

Answer:

The plane's acceleration is approximately \(-8.93 \, \text{m/s}^2\) (or in mph/s: \( \frac{0 - 300}{15} = -20 \, \text{mph/s} \)).