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ecosystem dynamics practice
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part 1: the 10% rule practice
in an ecosystem, only about 10% of the energy from one trophic level is transferred to the next. solve the following problems to understand how energy moves up the food chain.
- a flower has 5,000 units of energy. how much energy is available to the primary consumer?
- if a primary consumer receives 500 units of energy from eating plants, how much energy is available to the secondary consumer?
- a secondary consumer eats an organism that has 100 units of energy. how much energy will the tertiary consumer receive?
- if a hawk at the top of the food chain has 1 unit of energy available, how much energy did the producer start with?
- a grasshopper consumes a plant that has 3,750 units of energy. how much energy is available to the frog that eats the grasshopper?
- a wolf at the top of the food chain receives 2.3 joules of energy. how much energy did the producer originally have?
Step1: Calculate energy transfer
Use the formula \(E_{next}=E_{current}\times10\%\) (where \(E_{next}\) is energy for next trophic level and \(E_{current}\) is current energy).
Step2: Solve each problem
- For the flower (producer) with \(E = 5000\) units, energy to primary consumer: \(5000\times0.1=500\) units.
- Primary consumer has \(E = 500\) units, energy to secondary consumer: \(500\times0.1 = 50\) units.
- Secondary consumer has \(E = 100\) units, energy to tertiary consumer: \(100\times0.1=10\) units.
- Let producer energy be \(x\). After three - level transfer (\(x\times0.1\times0.1\times0.1 = 1\)), so \(x=\frac{1}{0.1\times0.1\times0.1}=1000\) units.
- Plant has \(E = 3750\) units (grasshopper is primary consumer), energy to frog (secondary consumer): \(3750\times0.1\times0.1 = 37.5\) units.
- Let producer energy be \(y\). After three - level transfer (\(y\times0.1\times0.1\times0.1=2.3\)), so \(y=\frac{2.3}{0.1\times0.1\times0.1}=2300\) Joules.
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- \(500\) units
- \(50\) units
- \(10\) units
- \(1000\) units
- \(37.5\) units
- \(2300\) Joules