Question

1. for each phenotype, give the genotypes that are possible for patrick.

a tall head (t) is dominant to short (t).
tall =
short =
pink body color (p) is dominant to yellow (p).
pink body =
yellow body =

1. spongebob squarepants recently met spongesusie roundpants at a dance. spongebob is heterozygous for his square shape, but spongesusie is round. create a punnett square to show the possibilities that would result if spongebob and spongesusie had children. hint: read question #2!

a. list the possible genotypes and phenotypes for their children.
b. what are the chances of a child with a square shape? _ out of _ or ___%
c. what are the chances of a child with a round shape? _ out of _ or ___%

1. patrick met patti at the dance. both of them are heterozygous for their pink body color, which is dominant over a yellow body color. create a punnett square to show the possibilities that would result if patrick and patti had children. hint: read question #3!

a. list the possible genotypes and phenotypes for their children.
b. what are the chances of a child with a pink body? _ out of _ or ___%
c. what are the chances of a child with a yellow body? _ out of _ or ___%

Explanation:

Step1: Genética de SpongeBob y SpongeSusie

SpongeBob es heterocigoto (Ss) para la forma cuadrada (dominante). SpongeSusie es redonda (genotipo ss, recesivo).

$$\begin{array}{c|cc} & S & s \\ \hline s & Ss & ss \\ s & Ss & ss \\ \end{array}$$

Step2: Posibles genotipos y fenotipos (Pregunta 4A)

Genotipos: Ss (cuadrado), ss (redondo). Fenotipos: 50% cuadrado (Ss), 50% redondo (ss).

Step3: Probabilidades (Pregunta 4B y 4C)

• Square: 2 out of 4 or 50% ($\frac{2}{4} = 0.5 = 50\%$)
• Round: 2 out of 4 or 50% ($\frac{2}{4} = 0.5 = 50\%$)

Step4: Genética de Patrick y Patti (Pregunta 5)

Ambos son heterocigotos (Pp) para el color de cuerpo rosado (dominante).

$$\begin{array}{c|cc} & P & p \\ \hline P & PP & Pp \\ p & Pp & pp \\ \end{array}$$

Step5: Posibles genotipos y fenotipos (Pregunta 5A)

Genotipos: PP (rosado), Pp (rosado), pp (amarillo). Fenotipos: 75% rosado (PP, Pp), 25% amarillo (pp).

Step6: Probabilidades (Pregunta 5B y 5C)

• Pink: 3 out of 4 or 75% ($\frac{3}{4} = 0.75 = 75\%$)
• Yellow: 1 out of 4 or 25% ($\frac{1}{4} = 0.25 = 25\%$)

Answer:

4A. Genotipos: Ss, ss. Fenotipos: Square (Ss), Round (ss).
4B. 2 out of 4 or 50%.
4C. 2 out of 4 or 50%.
5A. Genotipos: PP, Pp, pp. Fenotipos: Pink (PP, Pp), Yellow (pp).
5B. 3 out of 4 or 75%.
5C. 1 out of 4 or 25%.