Question

in each of the molecules drawn below one chemical bond is colored red. decide whether this bond is likely to be polar or not. if the bond is likely to be polar write down the chemical symbol for the atom which will have more negative charge.
the highlighted bond is polar and
the more negative atom is
the highlighted bond is nonpolar.
the highlighted bond is polar and
the more negative atom is
the highlighted bond is nonpolar.
the highlighted bond is polar and
the more negative atom is
the highlighted bond is nonpolar.

Explanation:

Step1: Determine polarity for \( H - N \) bond

Polarity of a bond depends on electronegativity difference. Electronegativity of \( H = 2.1 \), electronegativity of \( N=3.0 \). Since \( 3.0 - 2.1=0.9>0 \), the \( H - N \) bond is polar. The more electronegative atom (\( N \)) has more negative charge.

Step2: Determine polarity for \( Br - Br \) bond

Electronegativity of \( Br = 2.8 \). For \( Br - Br \), electronegativity difference \(=2.8 - 2.8 = 0\). So, the \( Br - Br \) bond is non - polar.

Step3: Determine polarity for \( Cl - F \) bond

Electronegativity of \( Cl = 3.0 \), electronegativity of \( F = 4.0 \). Electronegativity difference \(=4.0 - 3.0=1.0>0\). The \( Cl - F \) bond is polar. The more electronegative atom (\( F \)) has more negative charge.

Answer:

1. The highlighted \( H - N \) bond is polar and the more negative atom is \( N \).
2. The highlighted \( Br - Br \) bond is nonpolar.
3. The highlighted \( Cl - F \) bond is polar and the more negative atom is \( F \).