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QUESTION IMAGE

for each linear equation in the table, indicate whether the equation ha…

Question

for each linear equation in the table, indicate whether the equation has no solution, one solution, or infinitely many solutions. use the drop - down menus to choose the correct response for each equation. equation no solution/ one solution/ infinitely many solutions $5x + 13 = 13$ no solution $x - 3 = x + 3$ one solution $-4x - 8 = 4x + 8$ one solution

Explanation:

Response

To determine the number of solutions for each linear equation, we analyze them one by one:

Equation 1: \( 5x + 13 = 13 \)

Step 1: Subtract 13 from both sides

Subtract 13 from both sides of the equation:
\( 5x + 13 - 13 = 13 - 13 \)
Simplify: \( 5x = 0 \)

Step 2: Solve for \( x \)

Divide both sides by 5:
\( \frac{5x}{5} = \frac{0}{5} \)
Simplify: \( x = 0 \)

Since we found a unique value for \( x \), this equation has one solution.

Equation 2: \( x - 3 = x + 3 \)

Step 1: Subtract \( x \) from both sides

Subtract \( x \) from both sides:
\( x - 3 - x = x + 3 - x \)
Simplify: \( -3 = 3 \)

The statement \( -3 = 3 \) is false. There are no values of \( x \) that satisfy this equation, so it has no solution.

Equation 3: \( -4x - 8 = 4x + 8 \)

Step 1: Add \( 4x \) to both sides

Add \( 4x \) to both sides:
\( -4x - 8 + 4x = 4x + 8 + 4x \)
Simplify: \( -8 = 8x + 8 \)

Step 2: Subtract 8 from both sides

Subtract 8 from both sides:
\( -8 - 8 = 8x + 8 - 8 \)
Simplify: \( -16 = 8x \)

Step 3: Solve for \( x \)

Divide both sides by 8:
\( \frac{-16}{8} = \frac{8x}{8} \)
Simplify: \( -2 = x \)

Since we found a unique value for \( x \), this equation has one solution? Wait, no—wait, let’s recheck:

Wait, \( -4x - 8 = 4x + 8 \)
Add \( 4x \) to both sides: \( -8 = 8x + 8 \)
Subtract 8: \( -16 = 8x \)
Divide by 8: \( x = -2 \). So it does have one solution. Wait, but let’s confirm:

Wait, no—wait, the original equation: \( -4x - 8 = 4x + 8 \)
If \( x = -2 \), substitute back:
Left side: \( -4(-2) - 8 = 8 - 8 = 0 \)
Right side: \( 4(-2) + 8 = -8 + 8 = 0 \)
So \( x = -2 \) works. So it has one solution. Wait, but maybe I made a mistake earlier? Wait, no—let’s re-express:

Wait, the initial dropdown for \( -4x - 8 = 4x + 8 \) was set to “one solution,” which is correct. Wait, but let’s re-express the steps:

Wait, \( -4x - 8 = 4x + 8 \)
Bring all \( x \) terms to one side: \( -4x - 4x = 8 + 8 \)
\( -8x = 16 \)
\( x = -2 \). So yes, one solution.

Final Answers:
  • \( 5x + 13 = 13 \): One Solution
  • \( x - 3 = x + 3 \): No Solution
  • \( -4x - 8 = 4x + 8 \): One Solution

To summarize:

  1. \( 5x + 13 = 13 \): One Solution
  2. \( x - 3 = x + 3 \): No Solution
  3. \( -4x - 8 = 4x + 8 \): One Solution

Answer:

To determine the number of solutions for each linear equation, we analyze them one by one:

Equation 1: \( 5x + 13 = 13 \)

Step 1: Subtract 13 from both sides

Subtract 13 from both sides of the equation:
\( 5x + 13 - 13 = 13 - 13 \)
Simplify: \( 5x = 0 \)

Step 2: Solve for \( x \)

Divide both sides by 5:
\( \frac{5x}{5} = \frac{0}{5} \)
Simplify: \( x = 0 \)

Since we found a unique value for \( x \), this equation has one solution.

Equation 2: \( x - 3 = x + 3 \)

Step 1: Subtract \( x \) from both sides

Subtract \( x \) from both sides:
\( x - 3 - x = x + 3 - x \)
Simplify: \( -3 = 3 \)

The statement \( -3 = 3 \) is false. There are no values of \( x \) that satisfy this equation, so it has no solution.

Equation 3: \( -4x - 8 = 4x + 8 \)

Step 1: Add \( 4x \) to both sides

Add \( 4x \) to both sides:
\( -4x - 8 + 4x = 4x + 8 + 4x \)
Simplify: \( -8 = 8x + 8 \)

Step 2: Subtract 8 from both sides

Subtract 8 from both sides:
\( -8 - 8 = 8x + 8 - 8 \)
Simplify: \( -16 = 8x \)

Step 3: Solve for \( x \)

Divide both sides by 8:
\( \frac{-16}{8} = \frac{8x}{8} \)
Simplify: \( -2 = x \)

Since we found a unique value for \( x \), this equation has one solution? Wait, no—wait, let’s recheck:

Wait, \( -4x - 8 = 4x + 8 \)
Add \( 4x \) to both sides: \( -8 = 8x + 8 \)
Subtract 8: \( -16 = 8x \)
Divide by 8: \( x = -2 \). So it does have one solution. Wait, but let’s confirm:

Wait, no—wait, the original equation: \( -4x - 8 = 4x + 8 \)
If \( x = -2 \), substitute back:
Left side: \( -4(-2) - 8 = 8 - 8 = 0 \)
Right side: \( 4(-2) + 8 = -8 + 8 = 0 \)
So \( x = -2 \) works. So it has one solution. Wait, but maybe I made a mistake earlier? Wait, no—let’s re-express:

Wait, the initial dropdown for \( -4x - 8 = 4x + 8 \) was set to “one solution,” which is correct. Wait, but let’s re-express the steps:

Wait, \( -4x - 8 = 4x + 8 \)
Bring all \( x \) terms to one side: \( -4x - 4x = 8 + 8 \)
\( -8x = 16 \)
\( x = -2 \). So yes, one solution.

Final Answers:
  • \( 5x + 13 = 13 \): One Solution
  • \( x - 3 = x + 3 \): No Solution
  • \( -4x - 8 = 4x + 8 \): One Solution

To summarize:

  1. \( 5x + 13 = 13 \): One Solution
  2. \( x - 3 = x + 3 \): No Solution
  3. \( -4x - 8 = 4x + 8 \): One Solution