Question

during final exam weeks, many college students exercise to fuel their study sessions. data from a recent survey are shown in the venn diagram. let m be the event that the student exercises in the morning and let a be the event that the student exercises in the afternoon. what is the probability that a randomly chosen college student exercises in the morning or afternoon? 0.37 0.39 0.62 0.76

Explanation:

Step1: Apply the formula for \(P(M\cup A)\)

The formula for the probability of the union of two events is \(P(M\cup A)=P(M)+P(A)-P(M\cap A)\).

Step2: Calculate \(P(M)\), \(P(A)\) and \(P(M\cap A)\)

From the Venn - diagram:

• \(P(M)=0.25 + 0.37=0.62\)
• \(P(A)=0.37+0.14 = 0.51\)
• \(P(M\cap A)=0.37\)

Step3: Substitute values into the formula

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Answer:

\(0.76\)