Question

1. draw two different parallelograms that each have an area of 18 square units. parallelogram 1 parallelogram 2

Explanation:

Step1: Recall the area formula of a parallelogram

The area formula of a parallelogram is \(A = base\times height\). We know that \(A = 18\) square units.

Step2: Find pairs of base and height values

We need to find pairs of positive - integer values for base \(b\) and height \(h\) such that \(b\times h=18\).
The factor pairs of \(18\) are:

• If \(b = 2\) and \(h = 9\) (since \(2\times9 = 18\))
• If \(b=3\) and \(h = 6\) (since \(3\times6=18\))

Step3: Draw the parallelograms

• Parallelogram 1:
• Draw a parallelogram with a base of \(2\) units and a height of \(9\) units. For example, on the grid, start at a point. Move \(2\) units to the right for the base. Then, using the slope of the parallelogram (opposite sides are parallel), move up \(9\) units (perpendicular to the base) and complete the parallelogram.
• Parallelogram 2:
• Draw a parallelogram with a base of \(3\) units and a height of \(6\) units. Start at a point, move \(3\) units to the right for the base. Then move up \(6\) units (perpendicular to the base) and complete the parallelogram.

Answer:

Parallelogram 1: base = 2 units, height = 9 units; Parallelogram 2: base = 3 units, height = 6 units. (The actual drawing is done on the grid according to the base - height pairs)