Question

draw a line representing the
ise\ and a line representing the
un\ of the line. state the slope of the line in simplest form.
click twice to plot each segment.
click a segment to delete it.

Explanation:

Step1: Identify two points on the line

From the graph, the line passes through \((0,0)\) and \((6,1)\) (or other clear points, let's use these for simplicity).

Step2: Calculate rise and run

Rise is the change in \(y\), so \(y_2 - y_1 = 1 - 0 = 1\). Run is the change in \(x\), so \(x_2 - x_1 = 6 - 0 = 6\).

Step3: Find the slope

Slope \(m=\frac{\text{rise}}{\text{run}}=\frac{1}{6}\). (Wait, maybe better points: let's check another pair. Wait, the line also passes through \((-6, -1)\) and \((0,0)\). Then rise \(0 - (-1)=1\), run \(0 - (-6)=6\), same slope. Or maybe \((3, 0.5)\) but fractions can be tricky. Wait, maybe the correct points: looking at the graph, when \(x\) increases by 6, \(y\) increases by 1. So rise is 1, run is 6. So slope is \(\frac{1}{6}\)? Wait, no, maybe I misread. Wait, let's take two clear integer points. Let's see, the line goes through \((0,0)\) and \((6,1)\)? Wait, no, maybe \((-3, -0.5)\) and \((3, 0.5)\). Then rise \(0.5 - (-0.5)=1\), run \(3 - (-3)=6\). So slope is \(\frac{1}{6}\). Wait, but maybe the correct slope is \(\frac{1}{6}\)? Wait, no, maybe I made a mistake. Wait, let's check again. The line passes through \((0,0)\) and \((6,1)\), so slope is \(\frac{1 - 0}{6 - 0}=\frac{1}{6}\). Alternatively, if we take \((-6, -1)\) and \((0,0)\), slope is \(\frac{0 - (-1)}{0 - (-6)}=\frac{1}{6}\). So the slope is \(\frac{1}{6}\).

Answer:

The slope of the line is \(\frac{1}{6}\). (For drawing rise and run: from a point on the line, draw a vertical segment for rise (change in y) and horizontal segment for run (change in x), then calculate slope as rise over run.)