Question

draw the free - body diagram of the steel frame subjected to the load p as shown. what is the tension in cable ad?

Explanation:

Step1: Take moment about point E

$$\sum M_E = 0$$
$$P\times(2 + 2+ 2)-T_{AD}\times\frac{4}{5}\times6 = 0$$

Step2: Solve for \(T_{AD}\)

From \(6P-\frac{24}{5}T_{AD}=0\), we can get \(T_{AD}=\frac{5}{4}P\)

Answer:

\(\frac{5}{4}P\)