Question

divide. use base - ten blocks.

1. $4.9\div7 = \underline{\quad\quad}$
2. $3.6\div9 = \underline{\quad\quad}$
3. $2.4\div8 = \underline{\quad\quad}$
4. $6.48\div4 = \underline{\quad\quad}$
5. $3.01\div7 = \underline{\quad\quad}$
6. $4.26\div3 = \underline{\quad\quad}$

Explanation:

Step1: Solve \(4.9\div7\)

We can think of \(4.9\) as \(49\) tenths. Dividing \(49\) tenths by \(7\), we get \(49\div7 = 7\) tenths, which is \(0.7\). So \(4.9\div7=0.7\).

Step2: Solve \(3.6\div9\)

Treat \(3.6\) as \(36\) tenths. Dividing \(36\) tenths by \(9\), we have \(36\div9 = 4\) tenths, so \(3.6\div9 = 0.4\).

Step3: Solve \(2.4\div8\)

Consider \(2.4\) as \(24\) tenths. Dividing \(24\) tenths by \(8\), we get \(24\div8=3\) tenths, so \(2.4\div8 = 0.3\).

Step4: Solve \(6.48\div4\)

First, divide the whole number part: \(6\div4 = 1\) with a remainder of \(2\). Then, bring down the \(4\) (from the tenths place) to make \(24\) tenths. \(24\div4 = 6\) tenths. Then bring down the \(8\) (from the hundredths place) to make \(8\) hundredths. \(8\div4=2\) hundredths. Combining these, we get \(1.62\). So \(6.48\div4 = 1.62\).

Step5: Solve \(3.01\div7\)

We can think of \(3.01\) as \(301\) hundredths. Dividing \(301\) hundredths by \(7\), we have \(301\div7 = 43\) hundredths, which is \(0.43\). So \(3.01\div7=0.43\).

Step6: Solve \(4.26\div3\)

Divide the whole number part: \(4\div3 = 1\) with a remainder of \(1\). Bring down the \(2\) (tenths place) to make \(12\) tenths. \(12\div3 = 4\) tenths. Bring down the \(6\) (hundredths place) to make \(6\) hundredths. \(6\div3 = 2\) hundredths. Combining these, we get \(1.42\). So \(4.26\div3=1.42\).

Answer:

1. \(0.7\)
2. \(0.4\)
3. \(0.3\)
4. \(1.62\)
5. \(0.43\)
6. \(1.42\)