Question

distance in the coordinate plane quick check
daquan marks two points on the coordinate plane. one point is ( l(4,2) ) and the other point is ( m(7,6) ). what is the correct way for daquar
distance formula? (1 point)
( \bigcirc d=sqrt{(2 - 4)^{2}+(6 - 7)^{2}} )
( d=sqrt{(4 - 7)^{2}+(2 - 6)^{2}} )
( \bigcirc d=sqrt{(2 - 7)^{2}+(4 - 6)^{2}} )
( \bigcirc d=sqrt{(6 - 7)^{2}+(2 - 4)^{2}} )

Explanation:

Step1: Recall the distance formula

The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d = \sqrt{(x_1 - x_2)^2+(y_1 - y_2)^2}\).

Step2: Identify \(x_1,y_1,x_2,y_2\)

For points \(L(4,2)\) and \(M(7,6)\), \(x_1 = 4,y_1=2,x_2 = 7,y_2 = 6\).

Step3: Substitute into the formula

Substitute into \(d=\sqrt{(x_1 - x_2)^2+(y_1 - y_2)^2}\), we get \(d=\sqrt{(4 - 7)^2+(2 - 6)^2}\).

Answer:

\(d=\sqrt{(4 - 7)^2+(2 - 6)^2}\) (the option with this formula is the correct one)