Question

the distance between dontrells house and keikis house is blocks. co - ordinates (x2,y2) of point k: (-7,-10). co - ordinates (x1,y1) of point d: (-2,-11). q = √((x2 - x1)^2+(y2 - y1)^2). q = √((-7+2)^2+(-10 + 11)^2). q = √((-5)^2+(1)^2)

Explanation:

Step1: Identify the distance - formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Let $(x_1,y_1)=(-2,-11)$ and $(x_2,y_2)=(-7,-10)$.

Step2: Calculate the differences

First, find $x_2 - x_1$ and $y_2 - y_1$.
$x_2 - x_1=-7-(-2)=-7 + 2=-5$.
$y_2 - y_1=-10-(-11)=-10 + 11 = 1$.

Step3: Square the differences

$(x_2 - x_1)^2=(-5)^2 = 25$ and $(y_2 - y_1)^2=1^2 = 1$.

Step4: Sum the squared - differences

$(x_2 - x_1)^2+(y_2 - y_1)^2=25 + 1=26$.

Step5: Calculate the distance

$d=\sqrt{26}\approx5.1$

Answer:

$\sqrt{26}\approx5.1$