Question

the dimensions of mrs. longs lab are as follows: if it took mrs. long 60 seconds to walk the perimeter, what was mrs. longs average velocity after she completed one lap around her lab? oa 0 m/s ob 0.33 m/s oc 0.40 m/s od 3.0 m/s

Explanation:

Step1: Recall the formula for average velocity

Average velocity \(v=\frac{\Delta x}{\Delta t}\), where \(\Delta x\) is the displacement and \(\Delta t\) is the time interval.

Step2: Determine the displacement

When Mrs. Long completes one - lap around the lab (a closed - loop path), her initial and final positions are the same. So, the displacement \(\Delta x = 0\space m\). The time taken \(\Delta t=60\space s\).

Step3: Calculate the average velocity

Substitute \(\Delta x = 0\space m\) and \(\Delta t = 60\space s\) into the formula \(v=\frac{\Delta x}{\Delta t}\). We get \(v=\frac{0}{60}=0\space m/s\)

Answer:

A. \(0\frac{m}{s}\)