Question

differentiate.
y = 8^x
\frac{dy}{dx} = \square

Explanation:

Step1: Recall the formula for differentiating \(a^x\)

The derivative of \(y = a^x\) is \(y'=a^x\ln a\), where \(a>0,a
eq1\). In our case, \(a = 8\).

Step2: Apply the formula

Substitute \(a = 8\) into the formula \(y'=a^x\ln a\). So, if \(y = 8^x\), then \(\frac{dy}{dx}=8^x\ln 8\).

Answer:

\(8^x\ln 8\)