QUESTION IMAGE
Question
in the diagram, what is the measure of ∠wrs? 5° 7.5° 25° 37.5°
Step1: Identify supplementary angles
Angles \( (5x)^\circ \) and \( (25x + 30)^\circ \) are supplementary (they form a linear pair), so their sum is \( 180^\circ \).
Step2: Solve for \( x \)
Combine like terms:
Subtract 30 from both sides:
Divide by 30:
Step3: Find \( \angle WRS \)
\( \angle WRS \) is equal to \( (5x)^\circ \) (vertical angles or alternate angles, depending on the diagram). Substitute \( x = 5 \):
Wait, no, wait. Wait, actually, \( \angle WRS \) and \( (5x)^\circ \): Wait, maybe I made a mistake. Wait, let's re-examine. Wait, the angle \( (5x)^\circ \) and \( \angle WRS \): Wait, no, the angle \( (25x + 30)^\circ \) and the angle adjacent to \( \angle WRS \)? Wait, no, let's check again. Wait, the two angles \( (5x)^\circ \) and \( (25x + 30)^\circ \) are supplementary, so we solved \( 5x + 25x + 30 = 180 \), which gives \( 30x = 150 \), so \( x = 5 \). Then, \( \angle WRS \) is equal to \( (5x)^\circ \)? Wait, no, maybe \( \angle WRS \) is equal to \( (5x)^\circ \)? Wait, no, wait, the angle \( \angle WRS \) and \( (5x)^\circ \): Wait, maybe the diagram shows that \( \angle WRS \) is \( (5x)^\circ \)? Wait, no, let's check the answer options. Wait, if \( x = 5 \), then \( 5x = 25 \), but the options include 37.5. Wait, maybe I mixed up the angles. Wait, maybe \( \angle WRS \) is equal to the angle opposite to \( (5x)^\circ \), or maybe the angle \( \angle WRS \) is related to the other angle. Wait, no, let's re-express. Wait, the two angles \( (5x)^\circ \) and \( (25x + 30)^\circ \) are supplementary, so:
\( 5x + 25x + 30 = 180 \)
\( 30x = 150 \)
\( x = 5 \)
Then, \( \angle WRS \): Wait, maybe \( \angle WRS \) is equal to \( (5x)^\circ \)? But 5x is 25, which is an option. But wait, the options have 37.5. Wait, maybe I made a mistake in identifying the angle. Wait, maybe \( \angle WRS \) is equal to \( (25x + 30)^\circ \) divided by something? No, wait, let's check the diagram again. Wait, the diagram has lines intersecting at R. So, T---R---W is a straight line? No, T, R, W: T to R to W is a straight line? And V, R, S is another straight line? So, angle at R: T-R-W is a straight line, V-R-S is another straight line. So, angle TRV is \( (5x)^\circ \), angle TRS is \( (25x + 30)^\circ \). Then, angle TRV and angle TRS are supplementary, so \( 5x + 25x + 30 = 180 \), so \( 30x = 150 \), \( x = 5 \). Then, angle WRS is vertical to angle TRV, so angle WRS is \( (5x)^\circ = 25^\circ \). But the option 25 is there. But wait, the options also have 37.5. Wait, maybe I messed up the angle. Wait, maybe angle WRS is equal to the angle adjacent to \( (5x)^\circ \)? No, vertical angles are equal. Wait, maybe the diagram is different. Wait, maybe the two angles \( (5x)^\circ \) and \( (25x + 30)^\circ \) are not supplementary but form a linear pair with another angle. Wait, no, the problem is likely that I made a mistake. Wait, let's check again. Wait, maybe the angle \( \angle WRS \) is equal to \( (25x + 30)^\circ \) minus something? No, let's recalculate. Wait, if \( x = 5 \), then \( 25x + 30 = 25*5 + 30 = 125 + 30 = 155 \), and \( 5x = 25 \), so 25 + 155 = 180, which is correct. Then, angle WRS: if angle WRS is equal to \( (5x)^\circ \), then it's 25, which is an option. But the option 37.5 is also there. Wait, maybe the angle \( \angle WRS \) is equal to \( (5x)^\circ \), but maybe I misread the diagram. Wait, the options are 5, 7.5, 25, 37.5. If \( x = 7.5 \), then 5x = 37.5, and 25x + 30 = 25*7.5 +…
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25° (Option: 25°)