Question

the diagram shows two balls before they collide. what is the momentum of the system after the collision? (m_1 = 0.6 kg) (v_1 = 0.5 m/s) (m_2 = 0.5 kg) (v_2=- 0.2 m/s) (0.0 kgcdot m/s) (0.2 kgcdot m/s) (0.3 kgcdot m/s) (0.4 kgcdot m/s)

Explanation:

Step1: Recall momentum - conservation law

According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. The formula for momentum is $p = mv$, and the total initial momentum $p_{total - initial}=m_1v_1 + m_2v_2$.

Step2: Calculate the initial total momentum

Substitute the given values: $m_1 = 0.6\ kg$, $v_1=0.5\ m/s$, $m_2 = 0.5\ kg$, and $v_2=- 0.2\ m/s$ into the formula.
$p_{total - initial}=(0.6\times0.5)+(0.5\times(-0.2))$.
$p_{total - initial}=0.3-0.1$.
$p_{total - initial}=0.2\ kg\cdot m/s$.
Since $p_{total - initial}=p_{total - final}$, the momentum of the system after the collision is $0.2\ kg\cdot m/s$.

Answer:

0.2 kg·m/s