in the diagram below, $ \triangle efg \cong \triangle opq $, complete #2 - 7.
2. $ \overline { e f } \cong $
3. $ \angle p \cong $
4. $ \angle g \cong $
5. $ m \angle o = $
6. $ q o = $
7. $ \triangle g f e \cong $

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Accepted Answer

# Explanation:
## Step1: Use the property of congruent triangles
When $\triangle EFG\cong\triangle OPQ$, corresponding parts are congruent.
For $\overline{EF}$, its corresponding side in $\triangle OPQ$ is $\overline{OP}$. So $\overline{EF}\cong\overline{OP}$.
## Step2: For $\angle P$
$\angle P$ corresponds to $\angle F$ in $\triangle EFG$. So $\angle P\cong\angle F$.
## Step3: For $\angle G$
$\angle G$ corresponds to $\angle Q$ in $\triangle OPQ$. So $\angle G\cong\angle Q$.
## Step4: For $m\angle O$
$\angle O$ corresponds to $\angle E$ in $\triangle EFG$. Since $m\angle E = 110^{\circ}$, then $m\angle O=110^{\circ}$.
## Step5: For $QO$
$QO$ corresponds to $GE$ in $\triangle EFG$. Given $GE = 7\mathrm{km}$, so $QO = 7\mathrm{km}$.
## Step6: For $\triangle GFE$
$\triangle GFE$ corresponds to $\triangle QOP$ (by re - arranging the order of vertices according to congruence). So $\triangle GFE\cong\triangle QOP$.

# Answer:
2. $\overline{OP}$
3. $\angle F$
4. $\angle Q$
5. $110^{\circ}$
6. $7\mathrm{km}$
7. $\triangle QOP$

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QUESTION IMAGE

Question

Explanation:

Step1: Use the property of congruent triangles

Step2: For \(\angle P\)

Step3: For \(\angle G\)

Step4: For \(m\angle O\)

Step5: For \(QO\)

Step6: For \(\triangle GFE\)

Answer: