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the diagonal of a tv is 30 inches long. assuming that this diagonal for…

Question

the diagonal of a tv is 30 inches long. assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact length and width of the tv?

a. (60sqrt{2}) inches by (60sqrt{2}) inches
b. 15 inches by (15sqrt{3}) inches
c. (15sqrt{2}) inches by (15sqrt{2}) inches
d. 60 inches by (60sqrt{3}) inches

Explanation:

Identify the given values and target

The diagonal of a TV is \(d = 30\) inches. This diagonal forms a hypotenuse for two \(30^\circ\)-\(60^\circ\)-\(90^\circ\) right triangles. We need to find the exact length and width of the TV, which correspond to the legs of these right triangles.

Apply special right triangle ratios

Using the Special Right Triangles knowledge point

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State the final dimensions

The exact dimensions of the TV are \(15\) inches by \(15\sqrt{3}\) inches.

Answer:

  • A. \(60\sqrt{2}\) inches by \(60\sqrt{2}\) inches
  • B. 15 inches by \(15\sqrt{3}\) inches (Correct answer)
  • C. \(15\sqrt{2}\) inches by \(15\sqrt{2}\) inches
  • D. 60 inches by \(60\sqrt{3}\) inches