Question

if df = 70, de = 2x + 10, and ef = 6x + 4, then x =?

Explanation:

Step1: Use segment - addition postulate

Since $DF=DE + EF$, we substitute the given expressions: $70=(2x + 10)+(6x + 4)$.

Step2: Combine like - terms

First, simplify the right - hand side: $70=2x+6x + 10 + 4$, which gives $70=8x+14$.

Step3: Isolate the variable term

Subtract 14 from both sides: $70−14 = 8x+14−14$, so $56 = 8x$.

Step4: Solve for x

Divide both sides by 8: $\frac{56}{8}=x$, so $x = 7$.

Answer:

$x = 7$