determine what elements are denoted by the following electron configurations:
11) ( 1 s ^ { 2 } 2 s ^ { 2 } 2 p ^ { 6 } 3 s ^ { 2 } 3 p ^ { 4 } )
12) ( 1 s ^ { 2 } 2 s ^ { 2 } 2 p ^ { 6 } 3 s ^ { 2 } 3 p ^ { 6 } 4 s ^ { 2 } 3 d ^ { 10 } 4 p ^ { 6 } 5 s ^ { 1 } )
13) ( k r 5 s ^ { 2 } 4 d ^ { 10 } 5 p ^ { 3 } )
14) ( x e 6 s ^ { 2 } 4 f ^ { 14 } 5 d ^ { 6 } )
15) ( r n 7 s ^ { 2 } 5 f ^ { 11 } )

Question

determine what elements are denoted by the following electron configurations:
11) ( 1 s ^ { 2 } 2 s ^ { 2 } 2 p ^ { 6 } 3 s ^ { 2 } 3 p ^ { 4 } )
12) ( 1 s ^ { 2 } 2 s ^ { 2 } 2 p ^ { 6 } 3 s ^ { 2 } 3 p ^ { 6 } 4 s ^ { 2 } 3 d ^ { 10 } 4 p ^ { 6 } 5 s ^ { 1 } )
13) (  k r  5 s ^ { 2 } 4 d ^ { 10 } 5 p ^ { 3 } )
14) (  x e  6 s ^ { 2 } 4 f ^ { 14 } 5 d ^ { 6 } )
15) (  r n  7 s ^ { 2 } 5 f ^ { 11 } )

Accepted Answer

# Brief Explanations:
- For electron configuration $1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}$, count the total electrons: $2 + 2+6 + 2+4=16$. The element with atomic number $16$ is sulfur ($S$).
- For $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{1}$, count electrons: $2+2 + 6+2+6+2+10+6 + 1=39$. The element with atomic number $39$ is yttrium ($Y$).
- For $[Kr]5s^{2}4d^{10}5p^{3}$, $Kr$ has $36$ electrons. Add $2 + 10+3=15$. Total electrons $36 + 15=51$. The element with atomic number $51$ is antimony ($Sb$).
- For $[Xe]6s^{2}4f^{14}5d^{6}$, $Xe$ has $54$ electrons. Add $2+14 + 6=22$. Total electrons $54+22 = 76$. The element with atomic number $76$ is osmium ($Os$).
- For $[Rn]7s^{2}5f^{11}$, $Rn$ has $86$ electrons. Add $2+11 = 13$. Total electrons $86+13=99$. The element with atomic number $99$ is einsteinium ($Es$).

# Answer:
11) Sulfur ($S$)
12) Yttrium ($Y$)
13) Antimony ($Sb$)
14) Osmium ($Os$)
15) Einsteinium ($Es$)

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