Question

determine the quantity in moles of ag that are in 58.9 grams of ag₂o.

Explanation:

Step1: Calculate the molar mass of \(Ag_2O\)

The molar mass of \(Ag\) is \(M_{Ag}=107.87\ g/mol\), and the molar mass of \(O\) is \(M_O = 16.00\ g/mol\).
The molar mass of \(Ag_2O\) is \(M = 2\times107.87+16.00=231.74\ g/mol\)

Step2: Calculate the number of moles of \(Ag_2O\)

Use the formula \(n=\frac{m}{M}\), where \(m = 58.9\ g\) and \(M = 231.74\ g/mol\)
\(n_{Ag_2O}=\frac{58.9\ g}{231.74\ g/mol}\approx0.254\ mol\)

Step3: Calculate the number of moles of \(Ag\)

From the formula \(Ag_2O\), the mole ratio of \(Ag\) to \(Ag_2O\) is \(n_{Ag}:n_{Ag_2O}=2:1\)
So \(n_{Ag}=2\times n_{Ag_2O}\)
\(n_{Ag}=2\times0.254\ mol = 0.508\ mol\)

Answer:

\(0.508\ mol\)