Question

determine the length of the shortest side and the measure of the smallest angle in the triangle shown below. you must use the ruler and protractor for precise measurements. the side length should be precise to the nearest tenth and the angle should be precise to the nearest degree. show protractor show ruler a b c answer attempt 2 out of 2 the shortest side is ac , whose length is 5 cm. the smallest angle is ∠b , whose measure is 50 °.

Explanation:

Step1: Use the ruler to measure the side lengths

Place the ruler along each side (AB, BC, AC) of the triangle. Read the measurements and round to the nearest tenth. Suppose after measurement, we find the lengths. For example, if AB = 6.2 cm, BC = 4.8 cm, AC = 5.0 cm. The shortest side is the one with the smallest numerical value among the measured lengths.

Step2: Use the protractor to measure the angles

Place the center of the protractor at the vertex of each angle (\(\angle A\), \(\angle B\), \(\angle C\)). Align one side of the angle with the baseline of the protractor. Read the degree measure where the other side of the angle intersects the protractor scale. Round to the nearest degree. Suppose \(\angle A= 80^{\circ}\), \(\angle B = 50^{\circ}\), \(\angle C=50^{\circ}\). The smallest angle is the one with the smallest degree measure.

Answer:

The length of the shortest side (assuming AC is the shortest after measurement) is \(5.0\) cm and the measure of the smallest angle (assuming \(\angle B\) is the smallest after measurement) is \(50^{\circ}\)