Question

a cyclist is riding along a flat, straight, smooth bike path. the cyclist has a mass of 70.0 kg. their bike is made of carbon fiber and has a mass of 7.30 kg. they can accelerate from rest to approximately 1.70 m/s in about a minute.

1. what is the instantaneous acceleration of the cyclist during the first minute? show calculations in your response.

Explanation:

Step1: Identify the formula for acceleration

The formula for acceleration \(a=\frac{v - u}{t}\), where \(v\) is the final velocity, \(u\) is the initial velocity, and \(t\) is the time.

Step2: Determine the values of \(u\), \(v\), and \(t\)

The cyclist starts from rest, so \(u = 0\space m/s\). The final velocity \(v=1.70\space m/s\). The time \(t = 1\space minute=60\space s\).

Step3: Substitute the values into the formula

$$a=\frac{1.70 - 0}{60}$$

$$a=\frac{1.70}{60}\approx0.0283\space m/s^{2}$$

Answer:

The instantaneous acceleration of the cyclist during the first minute is approximately \(0.0283\space m/s^{2}\)