Question

current source that can supply 180 μa to the resor. the reason, 25. calculate the voltage for each value of i and r: (a) i = 2 a, r = 18 ω (b) i = 5 a, r = 56 ω (c) i = 2.5 a, r = 680 ω (d) i = 0.6 a, r = 47 ω (e) i = 0.1 a, r = 560 ω

Explanation:

To solve for the voltage \( V \) in each case, we use Ohm's Law, which states that \( V = I \times R \), where \( I \) is the current in amperes (A) and \( R \) is the resistance in ohms (\( \Omega \)).

Part (a)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 2 \, \text{A} \) and \( R = 18 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 2 \, \text{A} \times 18 \, \Omega = 36 \, \text{V}
\]

Part (b)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 5 \, \text{A} \) and \( R = 56 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 5 \, \text{A} \times 56 \, \Omega = 280 \, \text{V}
\]

Part (c)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 2.5 \, \text{A} \) and \( R = 680 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 2.5 \, \text{A} \times 680 \, \Omega = 1700 \, \text{V}
\]

Part (d)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 0.6 \, \text{A} \) and \( R = 47 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 0.6 \, \text{A} \times 47 \, \Omega = 28.2 \, \text{V}
\]

Part (e)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 0.1 \, \text{A} \) and \( R = 560 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 0.1 \, \text{A} \times 560 \, \Omega = 56 \, \text{V}
\]

Final Answers

(a) \( \boldsymbol{36 \, \text{V}} \)
(b) \( \boldsymbol{280 \, \text{V}} \)
(c) \( \boldsymbol{1700 \, \text{V}} \)
(d) \( \boldsymbol{28.2 \, \text{V}} \)
(e) \( \boldsymbol{56 \, \text{V}} \)

Answer:

To solve for the voltage \( V \) in each case, we use Ohm's Law, which states that \( V = I \times R \), where \( I \) is the current in amperes (A) and \( R \) is the resistance in ohms (\( \Omega \)).

Part (a)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 2 \, \text{A} \) and \( R = 18 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 2 \, \text{A} \times 18 \, \Omega = 36 \, \text{V}
\]

Part (b)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 5 \, \text{A} \) and \( R = 56 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 5 \, \text{A} \times 56 \, \Omega = 280 \, \text{V}
\]

Part (c)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 2.5 \, \text{A} \) and \( R = 680 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 2.5 \, \text{A} \times 680 \, \Omega = 1700 \, \text{V}
\]

Part (d)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 0.6 \, \text{A} \) and \( R = 47 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 0.6 \, \text{A} \times 47 \, \Omega = 28.2 \, \text{V}
\]

Part (e)

Step 1: Identify the values of \( I \) and \( R \)

We are given \( I = 0.1 \, \text{A} \) and \( R = 560 \, \Omega \).

Step 2: Apply Ohm's Law

Using the formula \( V = I \times R \), we substitute the given values:
\[
V = 0.1 \, \text{A} \times 560 \, \Omega = 56 \, \text{V}
\]

Final Answers

(a) \( \boldsymbol{36 \, \text{V}} \)
(b) \( \boldsymbol{280 \, \text{V}} \)
(c) \( \boldsymbol{1700 \, \text{V}} \)
(d) \( \boldsymbol{28.2 \, \text{V}} \)
(e) \( \boldsymbol{56 \, \text{V}} \)