Question

a crane lifts a load of steel that weighs 10⁵ n a distance of 100 m. it takes 5 minutes to complete the task. how much work is done by the crane? how much power does the crane produce?

Explanation:

Step1: Calculate Work Done

Work \( W \) is calculated as force \( F \) times distance \( d \), \( W = F \times d \). Here, \( F = 105 \, \text{N} \), \( d = 100 \, \text{m} \). So \( W = 105 \times 100 = 10500 \, \text{J} \).

Step2: Convert Time to Seconds

Time \( t = 5 \, \text{minutes} = 5 \times 60 = 300 \, \text{seconds} \).

Step3: Calculate Power

Power \( P \) is work done over time, \( P = \frac{W}{t} \). Substituting values, \( P = \frac{10500}{300} = 35 \, \text{W} \).

Answer:

Work done: \( 10500 \, \text{J} \), Power: \( 35 \, \text{W} \)