Question

copper wire reacts with a solution of silver nitrate to form solid silver. the liquid turns blue when copper ions are released into the solution as the reaction occurs. solid silver forming on a piece of copper wire the chemical equation for this reaction is shown below. ( mathrm{cu}(s)+2 mathrm{agno}_{3}(a q)
ightarrow mathrm{cu}left(mathrm{no}_{3}
ight)_{2}(a q)+2 mathrm{ag}(s) ) complete the table by classifying each substance from the equation as a reactant or a product.

Explanation:

Step1: Recall reactant and product definitions

In a chemical equation \(A + B
ightarrow C+D\), \(A\) and \(B\) are reactants (substances that react) and \(C\) and \(D\) are products (substances that are formed).

Step2: Analyze the given equation \(Cu(s)+2AgNO_{3}(aq)

ightarrow Cu(NO_{3})_{2}(aq) + 2Ag(s)\)

• For \(Cu\): It is on the left - hand side of the equation, so it is a reactant.
• For \(Cu(NO_{3})_{2}\): It is on the right - hand side of the equation, so it is a product.
• For \(Ag\): It is on the right - hand side of the equation, so it is a product.
• For \(AgNO_{3}\): It is on the left - hand side of the equation, so it is a reactant.

Answer:

Substance	Classification
copper nitrate \((Cu(NO_{3})_{2})\)	product
silver \((Ag)\)	product
silver nitrate \((AgNO_{3})\)	reactant