Question

a conveyor belt moves a 40 kg box at a velocity of 2 m/s. what is the kinetic energy of the box while it is on the conveyor belt?
40 j
80 j
160 j
1,600 j

Explanation:

Step1: Recall the formula for kinetic energy

The formula for kinetic energy is \(K = \frac{1}{2}mv^{2}\), where \(m\) is the mass and \(v\) is the velocity.

Step2: Substitute the given values into the formula

Given \(m = 40\space kg\) and \(v=2\space m/s\). Substitute into \(K=\frac{1}{2}\times40\times(2)^{2}\).
First, calculate \((2)^{2}=4\). Then \(\frac{1}{2}\times40 = 20\).
Finally, \(K=20\times4\).

Answer:

\(80\space J\) (the second option)