Question

construct the expression for ksp for solid bii₃ in aqueous solution. bii₃(s) ⇌ bi³⁺(aq) + 3 i⁻(aq) based on your knowledge of how the solid will dissociate in aqueous solution, construct the expression for the solubility constant, ksp. each reaction participant must be represented by one tile. ksp = bii₃ 2bii₃ bii₃² bi⁺ 3bi⁺ bi⁺³ bi³⁺ 3bi³⁺ bi³⁺³ i⁻ 3i⁻ i⁻³ i³⁻ 3i³⁻ i³⁻³

Explanation:

Step1: Recall Ksp definition

The solubility - product constant ($K_{sp}$) is the product of the molar concentrations of the ions in a saturated solution, each raised to the power equal to its coefficient in the balanced chemical equation for the dissociation of the solid.

Step2: Identify ion concentrations and exponents

For the dissociation of $BiI_{3}(s)
ightleftharpoons Bi^{3 + }(aq)+3I^{-}(aq)$, the coefficient of $Bi^{3 + }$ is 1 and the coefficient of $I^{-}$ is 3.
The $K_{sp}$ expression is $K_{sp}=[Bi^{3 + }][I^{-}]^{3}$.

Answer:

$K_{sp}=[Bi^{3 + }][I^{-}]^{3}$