Question

console screenshot:
enter your name and age: reilly 18
reilly, you are 18
program 1:
scanner input = new scanner(system in);
system.out.print(
name = input nextline();
age = input nextint();
system.out.print(name + + age);
program 2:
scanner input = new scanner(system in);
system.out.println(
name = input.next();
age = input nextint();
system out.print(name + + age);
program 3:
scanner input = new scanner(system in);
system.out.print(
name = input.next();
age = input.nextint();
system out print(name + + age);
which code was used to generate the
console screenshot?
program 3
program 1
program 2

Explanation:

The console input is "Reilly 18" (a single line with name and age separated by space). Program 1 uses nextLine() for name, which reads the entire line "Reilly 18" as the name, leaving no input for nextInt() (causing an error). Program 2 uses nextLine() for the prompt (likely printing the input instruction on a new line), but next() for name reads "Reilly" (the first token), and nextInt() reads 18 (the second token). The output matches "Reilly, you are 18". Program 3’s prompt uses print() (no new line), but the input method for name is consistent with Program 2, but the prompt formatting in Program 2 aligns with the console’s input line.

Answer:

Program 2