Question

consider the following series of arithmetic expressions.
a = 8;
b = 4;
c = 12;
a %= b - 2;
b = 11 - c % 3;
c = 3 * 2 - a;
which of the following statements is true?
a == 0 and b == 11 and c == 6
a == -2 and b == 1 and c == 6
a == -2 and b == 1 and c == 3

Explanation:

Step1: Calculate the new value of \(a\)

The operation \(a\%=b - 2\) is equivalent to \(a=a\%(b - 2)\). Given \(a = 8\) and \(b = 4\), then \(b-2=2\). So \(a = 8\%2=0\).

Step2: Calculate the new value of \(b\)

The operation \(b = 11-c\%3\). Given \(c = 12\), then \(c\%3=12\%3 = 0\). So \(b=11 - 0=11\).

Step3: Calculate the new value of \(c\)

The operation \(c=3*2 - a\). Since \(a = 0\) (from Step 1), then \(c=3*2-0=6\).

Answer:

\(a == 0\) and \(b == 11\) and \(c == 6\)