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consider circle t with radius 24 in and θ = 5π/6 radians. what is the l…

Question

consider circle t with radius 24 in and θ = 5π/6 radians. what is the length of minor arc sv? 20π in. 28π in. 40π in. 63π in

Explanation:

Step1: Recall arc - length formula

The formula for the length of an arc of a circle is $s = r\theta$, where $s$ is the arc - length, $r$ is the radius of the circle, and $\theta$ is the central angle in radians.

Step2: Substitute given values

We are given that $r = 24$ inches and $\theta=\frac{5\pi}{6}$ radians. Substitute these values into the formula: $s=24\times\frac{5\pi}{6}$.

Step3: Simplify the expression

$24\times\frac{5\pi}{6}=\frac{24\times5\pi}{6}= 20\pi$ inches.

Answer:

20π in.