Question

the concentration of hydroxide ion in an aqueous solution at 25 °c is 2.7e - 4 m. what is the concentration of the hydronium ion?

Explanation:

Step1: Recall the ion - product constant of water

At \(25^{\circ}C\), \(K_w=[H_3O^+][OH^-]=1.0\times10^{-14}\)

Step2: Solve for \([H_3O^+]\)

Given \([OH^-]=2.7\times 10^{-4}\space M\), we can rearrange the formula \(K_w=[H_3O^+][OH^-]\) to get \([H_3O^+]=\frac{K_w}{[OH^-]}\)

Substitute the values: \([H_3O^+]=\frac{1.0\times 10^{-14}}{2.7\times 10^{-4}}\)

$$
LATEXBLOCK0
$$

Answer:

\(3.7\times 10^{-11}\space M\)