Question

compare the results of applying the acceleration equation in the following two cases: (1) an object that goes from 0 to 10 m/s in 4 s, and (2) then goes from 10 m/s to 30 m/s in 8 s. (1) a=(v_f - v_i)/t = = (2) a=(v_f - v_i)/t = =

Explanation:

Step1: Calculate acceleration for case (1)

$a_1=\frac{v_{f1}-v_{i1}}{t_1}=\frac{10 - 0}{4}=\frac{10}{4}= 2.5\ m/s^{2}$

Step2: Calculate acceleration for case (2)

$a_2=\frac{v_{f2}-v_{i2}}{t_2}=\frac{30 - 10}{8}=\frac{20}{8}=2.5\ m/s^{2}$

Answer:

The acceleration in case (1) is $2.5\ m/s^{2}$ and the acceleration in case (2) is $2.5\ m/s^{2}$. The accelerations in both cases are equal.