QUESTION IMAGE
Question
- claudia is accelerating to get on the interstate. at the beginning of the south - facing on - ramp, she is traveling at 11 m/s. when she reaches the end of the on - ramp 9.0 seconds later, she is traveling at 29 m/s. assuming south to be the positive direction, what is claudias average rate of acceleration during this period?
2.0m/s²
-3.2m/s²
-2.0m/s²
3.2m/s²
Step1: Recall the formula for acceleration
The formula for acceleration \(a=\frac{v - u}{t}\), where \(v\) is the final velocity, \(u\) is the initial velocity, and \(t\) is the time.
Step2: Identify the values
Given \(u = 11m/s\), \(v=29m/s\), \(t = 9.0s\)
Step3: Substitute the values into the formula
\(a=\frac{29 - 11}{9}=\frac{18}{9}=2.0m/s^{2}\)
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2.0m/s²