Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

classify each chemical reaction: 2ch₃ch₂co₂h(l) + 7o₂(g) → 6co₂(g) + 6h…

Question

classify each chemical reaction:
2ch₃ch₂co₂h(l) + 7o₂(g) → 6co₂(g) + 6h₂o(g)
mgi₂(aq) + pb(no₃)₂(aq) → mg(no₃)₂(aq) + pbi₂(s)
na(s) + cl₂(g) → nacl₂(s)
koh(aq) + hclo₄(aq) → kclo₄(aq) + h₂o(l)

Explanation:

Brief Explanations
  • For the reaction \(2CH_{3}CH_{2}CO_{2}H(l)+7O_{2}(g)\to6CO_{2}(g)+6H_{2}O(g)\):
  • Combustion reactions involve a substance reacting with oxygen (\(O_{2}\)) to produce carbon dioxide (\(CO_{2}\)) and water (\(H_{2}O\)) (if the reactant contains \(C\) and \(H\)). Here, propanoic acid (\(CH_{3}CH_{2}CO_{2}H\)) reacts with \(O_{2}\) to form \(CO_{2}\) and \(H_{2}O\), so it is a combustion reaction.
  • For the reaction \(MgI_{2}(aq)+Pb(NO_{3})_{2}(aq)\to Mg(NO_{3})_{2}(aq)+PbI_{2}(s)\):
  • In double - replacement reactions, the cations and anions of two ionic compounds exchange partners. Here, \(Mg^{2 +}\) and \(Pb^{2+}\) exchange their anions (\(I^{-}\) and \(NO_{3}^{-}\)). Also, since \(PbI_{2}\) is a solid (precipitate) formed from aqueous solutions, it is also a precipitation reaction.
  • For the reaction \(Na(s)+Cl_{2}(g)\to NaCl(s)\):
  • Combination (synthesis) reactions involve two or more substances combining to form a single product. Here, sodium (\(Na\)) and chlorine (\(Cl_{2}\)) combine to form sodium chloride (\(NaCl\)).
  • For the reaction \(KOH(aq)+HClO_{4}(aq)\to KClO_{4}(aq)+H_{2}O(l)\):
  • Acid - base reactions (neutralization reactions) involve an acid (\(HClO_{4}\)) and a base (\(KOH\)) reacting to form a salt (\(KClO_{4}\)) and water (\(H_{2}O\)). It is also a double - replacement reaction as \(K^{+}\) and \(H^{+}\) exchange their anions (\(OH^{-}\) and \(ClO_{4}^{-}\)).

Answer:

  • \(2CH_{3}CH_{2}CO_{2}H(l)+7O_{2}(g)\to6CO_{2}(g)+6H_{2}O(g)\): combustion
  • \(MgI_{2}(aq)+Pb(NO_{3})_{2}(aq)\to Mg(NO_{3})_{2}(aq)+PbI_{2}(s)\): double replacement, precipitation
  • \(Na(s)+Cl_{2}(g)\to NaCl(s)\): combination
  • \(KOH(aq)+HClO_{4}(aq)\to KClO_{4}(aq)+H_{2}O(l)\): double replacement, acid - base