Question

chemistry the nucleus of a certain atom is $10^{-13}$ centimeters across. if the nucleus of a different atom is $10^{-11}$ centimeters across, how many orders of magnitude as great is the second nucleus?

Explanation:

Step1: Use the formula for order of magnitude difference

The formula for finding the difference in order of magnitude when comparing \(a = 10^{m}\) and \(b=10^{n}\) is \(|m - n|\). Here, \(m=- 11\) and \(n = - 13\).

Step2: Calculate the difference

Substitute the values into the formula: \(|-11-(-13)|=|-11 + 13|=|2| = 2\)

Answer:

\(2\)