Question

chemistry: nomenclature for ionic compounds
section i: write the name of each of the following ionic compounds. name the cation
use roman numerals to indicate the charge on the cation (+ ion) only when required.

1. ca₃p₂
2. mg₃(po₄)₂
3. kno₃
4. al(clo₂)₃
5. li₂b₄o₇
6. ti₂(so₃)₃
7. nif₄
8. cubr₂
9. sn(clo₃)₂
10. co(oh)₂

Explanation:

Step1: Name cation + anion (fixed charge)

$\text{Ca}_3\text{P}_2$: Calcium (Ca²⁺) + Phosphide (P³⁻)

Step2: Name cation + polyatomic anion

$\text{Mg}_3(\text{PO}_4)_2$: Magnesium (Mg²⁺) + Phosphate ($\text{PO}_4^{3-}$)

Step3: Name cation + polyatomic anion

$\text{KNO}_3$: Potassium (K⁺) + Nitrate ($\text{NO}_3^-$)

Step4: Name cation + polyatomic anion

$\text{Al(ClO}_2\text{)}_3$: Aluminum (Al³⁺) + Chlorite ($\text{ClO}_2^-$)

Step5: Name cation + polyatomic anion

$\text{Li}_2\text{B}_4\text{O}_7$: Lithium (Li⁺) + Tetraborate ($\text{B}_4\text{O}_7^{2-}$)

Step6: Find cation charge, name with Roman numeral

$\text{Ti}_2(\text{SO}_3)_3$: Ti charge = +3 (3×(-2) total sulfate charge, so 2Ti=+6 → Ti³⁺) → Titanium(III) Sulfite

Step7: Find cation charge, name with Roman numeral

$\text{NiF}_4$: F⁻×4=-4 → Ni⁴⁺ → Nickel(IV) Fluoride

Step8: Find cation charge, name with Roman numeral

$\text{CuBr}_2$: Br⁻×2=-2 → Cu²⁺ → Copper(II) Bromide

Step9: Find cation charge, name with Roman numeral

$\text{Sn(ClO}_3\text{)}_2$: $\text{ClO}_3^-$×2=-2 → Sn²⁺ → Tin(II) Chlorate

Step10: Find cation charge, name with Roman numeral

$\text{Co(OH)}_2$: OH⁻×2=-2 → Co²⁺ → Cobalt(II) Hydroxide

Answer:

1. Calcium Phosphide
2. Magnesium Phosphate
3. Potassium Nitrate
4. Aluminum Chlorite
5. Lithium Tetraborate
6. Titanium(III) Sulfite
7. Nickel(IV) Fluoride
8. Copper(II) Bromide
9. Tin(II) Chlorate
10. Cobalt(II) Hydroxide