Question

a chemist makes 200. ml of copper(ii) fluoride (cuf₂) working solution by adding distilled water to 70.0 ml of a 5.48 mm stock solution of copper(ii) fluoride in water. calculate the concentration of the chemists working solution. be sure your answer has the correct number of significant digits. mm

Explanation:

Step1: Recall the dilution formula

The dilution formula is \(C_1V_1 = C_2V_2\), where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.

Step2: Identify the given values

Here, \(C_1 = 5.48\space mM\), \(V_1=70.0\space mL\), and \(V_2 = 200.\space mL\).

Step3: Solve for \(C_2\)

Rearrange the formula to \(C_2=\frac{C_1V_1}{V_2}\). Substitute the values: \(C_2=\frac{5.48\times70.0}{200.}\).
First, calculate \(5.48\times70.0 = 383.6\). Then, \(\frac{383.6}{200.}=1.918\).

Answer:

\(1.92\space mM\)