Question

#4 - chemical systems and equilibrium (part 1)
question 8 (1 point)
if $k_{eq}$ is very large ($k >> 1$), the equilibrium lies very much to the left and the composition of the equilibrium mixture is mostly reactants.
true
false
question 9 (1 point)
if a solid is added to a heterogeneous equilibrium, the position of equilibrium will change.
true
false

Explanation:

Question 8

The equilibrium constant \( K_{eq} \) is the ratio of product concentrations to reactant concentrations (each raised to their stoichiometric coefficients). If \( K_{eq} \gg 1 \), the numerator (products) is much larger than the denominator (reactants), so the equilibrium lies to the right (mostly products), not the left. Thus, the statement is false.

In heterogeneous equilibria, the concentration of a solid (or pure liquid) is considered constant (activity = 1) and does not appear in the equilibrium expression. Adding more solid does not change its "concentration" or activity, so it has no effect on the equilibrium position. Thus, the statement is false.

Answer:

False

Question 9