Question

the chemical formula for glucose is c₆h₁₂o₆. what is the percent composition for oxygen in glucose? molar masses to use: c = 12.011; h = 1.008; o = 15.999
a 180.156%
b 43.28%
c 53.28%
d 6.71%
question 19
the lewis dot diagram for water is shown below. select two of the terms that describe this molecule’s lewis dot diagram.
a tetrahedra
b bent
c linear
d nonpolar

Explanation:

Step1: Calculate molar mass of glucose

Molar mass of \( C_6H_{12}O_6 \) = \( 6\times12.011 + 12\times1.008 + 6\times15.999 \)
= \( 72.066 + 12.096 + 95.994 \)
= \( 180.156 \) g/mol.

Step2: Calculate mass of oxygen in glucose

Mass of O = \( 6\times15.999 = 95.994 \) g/mol.

Step3: Calculate percent composition of O

Percent composition = \( \frac{\text{Mass of O}}{\text{Molar mass of glucose}} \times 100\% \)
= \( \frac{95.994}{180.156} \times 100\% \approx 53.28\% \)

Answer:

C. 53.28%