Question

chemical compounds assessment
part 1: interpreting chemical formulas _/10
instructions: please identify the number and types of atoms in the following chemical formulas.
ch₃cooh c = 2, h = 4, o = 2
h₂o
co₂
ch₄
c₆h₁₂o₆
h₂so₄
(nh₄)₃po₄
na₂co₃
ca₃(po₄)₂
al₂(so₄)₃
pb(no₃)₄

Explanation:

Step1: Analyze \(H_2O\)

For \(H_2O\), the sub - script after \(H\) is \(2\) and after \(O\) is \(1\) (when no sub - script is written, it is assumed to be \(1\)). So, \(H = 2\), \(O=1\)

Step2: Analyze \(CO_2\)

In \(CO_2\), the sub - script of \(C\) is \(1\) and of \(O\) is \(2\). So, \(C = 1\), \(O = 2\)

Step3: Analyze \(CH_4\)

For \(CH_4\), the sub - script of \(C\) is \(1\) and of \(H\) is \(4\). So, \(C = 1\), \(H=4\)

Step4: Analyze \(C_6H_{12}O_6\)

In \(C_6H_{12}O_6\), the sub - script of \(C\) is \(6\), of \(H\) is \(12\) and of \(O\) is \(6\). So, \(C = 6\), \(H = 12\), \(O = 6\)

Step5: Analyze \(H_2SO_4\)

For \(H_2SO_4\), the sub - script of \(H\) is \(2\), of \(S\) is \(1\) and of \(O\) is \(4\). So, \(H = 2\), \(S = 1\), \(O = 4\)

Step6: Analyze \((NH_4)_3PO_4\)

In \((NH_4)_3PO_4\), for \(N\): \(3\times1 = 3\) (from \(NH_4\) group), for \(H\): \(3\times4=12\), for \(P\): \(1\), for \(O\): \(4\). So, \(N = 3\), \(H = 12\), \(P = 1\), \(O = 4\)

Step7: Analyze \(Na_2CO_3\)

For \(Na_2CO_3\), the sub - script of \(Na\) is \(2\), of \(C\) is \(1\) and of \(O\) is \(3\). So, \(Na = 2\), \(C = 1\), \(O = 3\)

Step8: Analyze \(Ca_3(PO_4)_2\)

In \(Ca_3(PO_4)_2\), for \(Ca\): \(3\), for \(P\): \(2\times1 = 2\), for \(O\): \(2\times4=8\). So, \(Ca = 3\), \(P = 2\), \(O = 8\)

Step9: Analyze \(Al_2(SO_4)_3\)

For \(Al_2(SO_4)_3\), for \(Al\): \(2\), for \(S\): \(3\times1 = 3\), for \(O\): \(3\times4 = 12\). So, \(Al = 2\), \(S = 3\), \(O = 12\)

Step10: Analyze \(Pb(NO_3)_4\)

In \(Pb(NO_3)_4\), for \(Pb\): \(1\), for \(N\): \(4\times1 = 4\), for \(O\): \(4\times3=12\). So, \(Pb = 1\), \(N = 4\), \(O = 12\)

Answer:

Chemical Compound	Elements in Compound and Number of Atoms
\(CO_2\)	\(C = 1\), \(O = 2\)
\(CH_4\)	\(C = 1\), \(H = 4\)
\(C_6H_{12}O_6\)	\(C = 6\), \(H = 12\), \(O = 6\)
\(H_2SO_4\)	\(H = 2\), \(S = 1\), \(O = 4\)
\((NH_4)_3PO_4\)	\(N = 3\), \(H = 12\), \(P = 1\), \(O = 4\)
\(Na_2CO_3\)	\(Na = 2\), \(C = 1\), \(O = 3\)
\(Ca_3(PO_4)_2\)	\(Ca = 3\), \(P = 2\), \(O = 8\)
\(Al_2(SO_4)_3\)	\(Al = 2\), \(S = 3\), \(O = 12\)
\(Pb(NO_3)_4\)	\(Pb = 1\), \(N = 4\), \(O = 12\)