Question

a certain television is advertised as a 68 - inch tv (the diagonal length). if the height of the tv is 48 inches, how wide is the tv? round to the nearest tenth of an inch.

Explanation:

Step1: Apply Pythagorean theorem

Let the width be \(w\). By Pythagorean theorem \(w^{2}+h^{2}=d^{2}\), where \(h = 48\), \(d=60\). So \(w^{2}=d^{2}-h^{2}\).

Step2: Substitute values

\(w^{2}=60^{2}-48^{2}=3600 - 2304=1296\).

Step3: Solve for \(w\)

\(w=\sqrt{1296}=36.0\)

Answer:

\(36.0\) inches