Question

a cement path consists of six equal - sized cement squares arranged in a row to form a rectangle. if the total area of the path is 96 square feet, what is the length in feet of the path?

Explanation:

Step1: Find area of one square

There are 6 equal - sized squares and the total area is 96 square feet. So the area of one square, let's call it \(A\), is \(A=\frac{96}{6}\).
\(A = 16\) square feet.

Step2: Find side length of one square

The area of a square is given by the formula \(A = s^{2}\), where \(s\) is the side length. Since \(A = 16\), we have \(s^{2}=16\), so \(s=\sqrt{16}=4\) feet.

Step3: Find length of the path

The path is made up of 6 squares arranged in a row. The length of the path will be the number of squares times the side length of one square. So the length \(L=6\times s\).
Substituting \(s = 4\), we get \(L = 6\times4=24\) feet.

Answer:

24