Question

a cell with a water potential of -1.5 bars is placed in a beaker of sugar water with $psi s = 1.5$ bars. in which direction will the net flow of water be? no net flow of water into the cell out of the cell

Explanation:

Step1: Calculate the water potential of the sugar water

Assume the pressure potential ($\Psi_p$) of the sugar water is $0$ (as it is an open beaker). The formula for water potential ($\Psi$) is $\Psi=\Psi_s+\Psi_p$. Given $\Psi_s = 1.5$ bars and $\Psi_p=0$, so $\Psi_{sugar - water}=1.5 + 0=1.5$ bars.

Step2: Compare the water potentials

The water potential of the cell is $\Psi_{cell}=- 1.5$ bars. Water moves from an area of higher water potential to an area of lower water potential. Since $1.5>-1.5$ (water potential of sugar - water > water potential of cell)

Answer:

Out of the cell