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Question
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a circular sector has a central angle of \\( \frac{\pi}{6} \\) radians and a radius of 9 ft.
what is the area of the sector?
use 3.14 for pi. round your answer to the nearest tenth.
enter your answer in the box.
area = \\( \square \\) \\( \mathrm{ft}^{2} \\)
Step1: Recall the formula for the area of a sector
The formula for the area of a sector is \(A=\frac{1}{2}r^{2}\theta\), where \(r\) is the radius and \(\theta\) is the central angle in radians.
Step2: Substitute the given values into the formula
Given \(r = 9\) ft and \(\theta=\frac{\pi}{6}\). Substitute into \(A=\frac{1}{2}r^{2}\theta\), we get \(A=\frac{1}{2}\times9^{2}\times\frac{\pi}{6}\).
First, calculate \(9^{2}=81\). Then the formula becomes \(A=\frac{1}{2}\times81\times\frac{\pi}{6}\).
\(A=\frac{81\pi}{12}\).
Since \(\pi = 3.14\), then \(A=\frac{81\times3.14}{12}\).
\(81\times3.14 = 254.34\). So \(A=\frac{254.34}{12}\).
Step3: Calculate the value
\(\frac{254.34}{12}=21.195\).
Step4: Round to the nearest tenth
Rounding \(21.195\) to the nearest tenth. The digit in the hundredth place is \(9\), so we round up the digit in the tenth place. \(21.195\approx21.2\).
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\(21.2\)