Question

1. calculation

a 2 kg object moves in a horizontal circle of radius 3 m with a constant speed of 6 m/s. what is the magnitude of the centripetal force acting on the object?

Explanation:

Step1: Identify the formula

The formula for centripetal force is $F = m\frac{v^{2}}{r}$, where $m$ is the mass, $v$ is the velocity and $r$ is the radius.

Step2: Substitute the values

Given $m = 2\ kg$, $v = 6\ m/s$ and $r = 3\ m$. Substitute into the formula: $F=2\times\frac{6^{2}}{3}$.

Step3: Calculate the result

First, calculate $6^{2}=36$. Then $\frac{36}{3}=12$. Finally, $2\times12 = 24\ N$.

Answer:

$24\ N$