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calculating the standard deviation of a discrete random variable a popu…

Question

calculating the standard deviation of a discrete random variable
a popular streaming service surveyed all of the students at a school about the number of tv shows they streamed last friday night, then recorded the results.
let ( m ) = the number of tv shows streamed last friday night.

number of shows streamedprobability
10.203
20.326
30.187
40.174
50.015

calculate the standard deviation of ( m ).

Explanation:

Step1: Calculate the expected value \( E(M) \)

The formula for the expected value of a discrete random variable is \( E(M) = \sum_{i} m_i \cdot P(m_i) \), where \( m_i \) is the value of the random variable and \( P(m_i) \) is its corresponding probability.

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Step2: Calculate the variance \( \text{Var}(M) \)

The formula for the variance of a discrete random variable is \( \text{Var}(M) = \sum_{i} (m_i - E(M))^2 \cdot P(m_i) \).

First, calculate \( (m_i - E(M))^2 \) for each \( m_i \):

  • For \( m = 0 \): \( (0 - 2.187)^2 = (-2.187)^2 = 4.782969 \), then \( 4.782969 \cdot 0.095 \approx 0.454382 \)
  • For \( m = 1 \): \( (1 - 2.187)^2 = (-1.187)^2 = 1.408969 \), then \( 1.408969 \cdot 0.203 \approx 0.286021 \)
  • For \( m = 2 \): \( (2 - 2.187)^2 = (-0.187)^2 = 0.034969 \), then \( 0.034969 \cdot 0.326 \approx 0.011400 \)
  • For \( m = 3 \): \( (3 - 2.187)^2 = (0.813)^2 = 0.660969 \), then \( 0.660969 \cdot 0.187 \approx 0.123601 \)
  • For \( m = 4 \): \( (4 - 2.187)^2 = (1.813)^2 = 3.286969 \), then \( 3.286969 \cdot 0.174 \approx 0.571933 \)
  • For \( m = 5 \): \( (5 - 2.187)^2 = (2.813)^2 = 7.912969 \), then \( 7.912969 \cdot 0.015 \approx 0.118695 \)

Now, sum these values to get the variance:

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Step3: Calculate the standard deviation \( \sigma \)

The standard deviation is the square root of the variance, so \( \sigma = \sqrt{\text{Var}(M)} \).

$$ \sigma = \sqrt{1.566032} \approx 1.251 $$

Answer:

The standard deviation of \( M \) is approximately \( 1.25 \) (rounded to two decimal places) or more precisely \( \approx 1.251 \).