Question

calculate the volume in milliliters of a 3.1 mol/l silver nitrate solution that contains 37.5 mmol of silver nitrate (agno3). round your answer to 2 significant digits.

Explanation:

Step1: Convert millimoles to moles

Since \(1\space mol = 1000\space mmol\), then \(n = 37.5\space mmol=\frac{37.5}{1000}\space mol = 0.0375\space mol\)

Step2: Use the formula \(V=\frac{n}{C}\)

Given \(C = 3.1\space mol/L\) and \(n=0.0375\space mol\). Substitute into the formula \(V=\frac{n}{C}\), we get \(V=\frac{0.0375\space mol}{3.1\space mol/L}\approx0.012097\space L\)

Step3: Convert liters to milliliters

Since \(1\space L = 1000\space mL\), then \(V = 0.012097\space L\times1000 = 12.097\space mL\)

Step4: Round to 2 significant digits

Rounding \(12.097\) to 2 significant digits gives \(12\space mL\)

Answer:

\(12\)