QUESTION IMAGE
Question
- a businesss revenue is modeled by $r(x) = -4x^2 + 80x$, where $x$ is the number of units sold. how many units should be sold to maximize revenue?
a. 20 units
b. 22 units
c. 18 units
d. 10 units
- what are the roots of the quadratic equation $4x^2 - 4x + 1 = 0?$
a. $x = 2$
b. $x = 1$ and $x = 2$
c. $x = 1$ and $x = 3$
d. $x = \frac{1}{2}$
Question 1:
Step1: Identify the function type
The revenue function \( R(x) = -4x^2 + 80x \) is a quadratic function in the form \( ax^2 + bx + c \), where \( a = -4 \), \( b = 80 \), and \( c = 0 \). For a quadratic function, if \( a < 0 \), the parabola opens downward, and the vertex is the maximum point.
Step2: Find the x-coordinate of the vertex
The formula for the x-coordinate of the vertex of a quadratic function \( f(x) = ax^2 + bx + c \) is \( x = -\frac{b}{2a} \). Substituting \( a = -4 \) and \( b = 80 \) into the formula:
Wait, that seems conflicting with the options? Wait, no, wait, let's recalculate. Wait, \( a = -4 \), \( b = 80 \). So \( x = -b/(2a) = -80/(2(-4)) = -80/(-8) = 10 \)? But option d is 10 units. Wait, but let's check again. Wait, maybe I made a mistake? Wait, the function is \( R(x) = -4x^2 + 80x \). So \( a = -4 \), \( b = 80 \). Then \( x = -b/(2a) = -80/(2(-4)) = -80/-8 = 10 \). So the number of units to maximize revenue is 10? But let's check the options. Option d is 10 units. Wait, but let's verify by expanding or using another method. Alternatively, maybe I misread the function. Wait, the function is \( R(x) = -4x^2 + 80x \). Let's factor it: \( R(x) = -4x(x - 20) \). The roots are at \( x = 0 \) and \( x = 20 \). The vertex is at the midpoint of the roots, so \( (0 + 20)/2 = 10 \). Yes, that's correct. So the x-coordinate of the vertex is 10, so 10 units should be sold to maximize revenue.
Step1: Identify the quadratic equation
The quadratic equation is \( 4x^2 - 4x + 1 = 0 \). We can solve this using factoring, completing the square, or the quadratic formula. Let's try factoring. Notice that \( 4x^2 - 4x + 1 \) is a perfect square trinomial. \( (2x - 1)^2 = 4x^2 - 4x + 1 \). So the equation becomes \( (2x - 1)^2 = 0 \).
Step2: Solve for x
Taking the square root of both sides: \( 2x - 1 = 0 \). Solving for x: \( 2x = 1 \) => \( x = \frac{1}{2} \). So the root is \( x = \frac{1}{2} \) (a repeated root).
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d. 10 units